Maths
Number
Multi-digit addition
Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practise!

Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practise!

Watch videos

Start exercises

Show worksheets

Ask teachers

Rating

Be the first to give a rating!

You must be logged in to be able to give a rating.

Wow, thank you!
Please rate us on Google too! We look forward to it!

Go to Google

The authors

Team Digital

Basics on the topic Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practise!

Join Razzi and practise adding two two digit numbers using base ten blocks with regrouping.

Transcript Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practise!

Razzi says get these items ready because today we're going to practise using place value to add two digit numbers (regrouping). It's time to begin! Remember that there are many strategies to add, like using place value. Place value is the value that each digit has, depending on where it is in the number. Let's use base ten blocks to add and regroup with place value. What is twenty-five plus thirty-eight? You can add the tens rods together first, then the ones blocks. Then, if you have enough ones to make a ten, regroup and add it to the tens place. Did you also get sixty-three? Let's tackle the next problem! What is thirty-six plus thirty-four? You can add the tens rods together first, then the ones blocks. Then, if you have enough ones to make a ten, regroup and add it to the tens place. Did you also get seventy? Let's tackle the final problem! What is forty-six plus thirty-seven? You can add the tens rods together first, then the ones blocks. Then, if you have enough ones to make a ten, regroup and add it to the tens place. Did you also get eighty-three? Razzi had so much fun practising with you today! See you next time!

Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practise! exercise

Would you like to apply the knowledge you’ve learnt? You can review and practice it with the tasks for the video Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practise!.

Find the sum.
Hints

How many blue tens rods will there be at first? 2 + 3 = 5.

How many green ones blocks will there be at first? 6 + 5 = 11.

We have enough ones to make a ten, so we regroup and add them to the tens place on the left.

Add the tens rods together and the ones blocks together to calculate the sum.

Solution
- Add the tens rods: 2 + 3 = 5
- Add the ones blocks: 6 + 5 = 11
- There are enough ones to make a ten, so regroup and add them to the tens place.
- Finally, add the tens rods together and the ones blocks together to calculate the sum:
- For the tens rods: 2 + 3 + 1 = 6. 6 is the number in the tens place of the sum.
- For the ones blocks: there is only 1 left. 1 is the number in the ones place of the sum.
The sum is 61.
Find each sum.
Hints

First, add the tens rods.
For example, 29 + 27 has 2 + 2 = 4 tens rods.

Then, add the ones blocks.
29 + 27 has 9 + 7 = 16 ones blocks.

If there are enough ones to make a ten, regroup and add them to the tens place on the left.

Add the tens rods together and the ones blocks together to find the final sum.

Solution
To solve 29 + 27:
- Add the tens rods together: 2 + 2 = 4
- Add the ones blocks together: 9 + 7 = 16
- There are enough ones to make a ten, so regroup and add them to the tens place.
- Finally, add the tens rods together and the ones blocks together to calculate the sum.
- For the tens rods: 2 + 2 + 1 = 5. 5 is the number in the tens place of the sum.
- For the ones blocks: 4 + 2 = 6. 6 is the number in the ones place of the sum.
The sum is 56.
________________________________________________________
* 23 + 17 = 40
* 45 + 28 = 73
Find each sum.
Hints

First, add the tens rods.
For example, 18 + 49 has 1 + 4 = 5 tens rods.

Then, add the ones blocks.
For example, 18 + 49 has 8 + 9 = 17 ones blocks.

If there are enough ones to make a ten, regroup and add them to the tens place.

Add the tens rods together and the ones blocks together to calculate the sum.

Solution
The matching pairs are:
- 18 + 49 = 67
- 15 + 17 = 32
- 27 + 23 = 50
- 42 + 38 = 80
To solve 18 + 49 we can use the image above:
- Add the tens rods: 1 + 4 = 5
- Add the ones blocks: 8 + 9 = 17
- There are enough ones to make a ten, so regroup and add them to the tens place.
- Finally, add the tens rods together and the ones blocks together to calculate the sum:
- For the tens rods: 1 + 4 + 1 = 6. 6 is the number in the tens place of the sum.
- For the ones blocks: 3 + 4 = 7. 7 is the number in the ones place of the sum.
The sum is 67.
Solve the addition problem.
Hints

In order to find how many total guests Razzi needs to invite, we add the number of friends and the number of family members.

Razzi has 16 friends and 55 family members.
Therefore, we add 16 + 55.

16 + 55 has 6 tens rods and 11 ones blocks.

There are enough ones to make a ten, so regroup and add them to the tens place.

Solution
In order to find how many total guests Razzi needs to invite, we add the number of friends and the number of family members. Razzi has 16 friends and 55 family members. Therefore, we add 16 + 55.
- 16 + 55 has 6 tens rods and 11 ones blocks.
- There are enough ones to make a ten, so regroup and add them to the tens place on the left.
- Finally, add the tens rods together and the ones blocks together to calculate the sum:
- For the tens rods: 1 + 5 + 1 = 7. 7 is the number in the tens place of the sum.
- For the ones blocks: there is only 1 left. 1 is the number in the ones place of the sum.
The sum is 71.
Razzi needs to invite 71 guests to his party.
Complete the addition problem.
Hints

How many blue tens rods will there be at first? 2 + 1 = 3.

How many green ones blocks will there be at first? 9 + 5 = 14.

There are enough ones to make a ten, so regroup and add them to the tens place.

Add the tens rods together and the ones blocks together to calculate the sum.

Solution
- Add the tens blocks together: 2 + 1 = 3
Add the ones blocks together: 9 + 5 = 14
There are enough ones to make a ten, so regroup and add them to the tens place on the left.

Finally, add the tens rods together and the ones blocks together to calculate the sum.
- For the tens rods: 2 + 1 + 1 = 4. *4 is the number in the tens place of the sum.
- For the ones blocks: there are 4 left. 4 is the number in the ones place of the sum.
The sum is 44.
Complete each addition problem.
Hints

For 79 + ___ = 93:
To get a 3 in the ones place of the sum, we need to find a number that when added to the 9 in the ones place of 79 makes 13.
9 + 4 = 13. Therefore, 4 is in the ones place of our answer.

Use the image to help you solve 81 + 29.
The tens rods from both numbers have been grouped to make a total of 10 tens rods. Are there enough one blocks to make another ten?

Solution
To solve 79 + ___ = 93:
- We need to find the number that we add to 79 to get 93. (see image)
- To get a 3 in the ones place of the sum, we need to find a number that when added to the 9 in the ones place of 79 makes 13.
- 9 + 4 = 13. Therefore, 4 is in the ones place of our answer.
- 79 + 14 = 93. The answer is 14.
To solve ___ + 23 = 81:
- We need to find the number that we add to 23 to get 81.
- To get a 1 in the ones place of the sum, we need to find a number that when added to the 3 in the ones place of 23 makes 11.
- 8 + 3 = 11. Therefore, 8 is in the ones place of our answer.
- 58 + 23 = 81. The answer is 58.
To solve 81 + 29 = ___:
- Add the tens rods: 8 + 2 = 10
- Add the ones blocks: 1 + 9 = 10
- We have 10 tens rods and 10 ones blocks.
- We have enough ones to make a ten, so we regroup and add them to the tens place. There are now 0 ones blocks.
- Finally, we add the tens rods together and the ones blocks together to calculate the sum.
- 81 + 29 = 110. The answer is 110.