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Side and Angle Conditions for a Triangle

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Side and Angle Conditions for a Triangle

Triangles are among the simplest and most studied shapes in geometry, used in everything from architectural design to trigonometry classes. A triangle is a three-sided polygon, and its properties are fundamental to understanding many aspects of geometry. Constructing triangles may seem easy at first, but there are important factors to take into account.

Triangles are shapes with three straight sides and three angles. The sum of the interior angles in a triangle always equals $180$ degrees, and the length of any side must be less than the sum of the other two sides (triangle inequality theorem).

Side and Angle Conditions for a Triangle – Explanation

The properties of triangles vary depending on the lengths of their sides and the measures of their angles. Here are the basic rules and conditions:

Rule Name Description
Triangle Inequality Theorem The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Sum of Angles The sum of the interior angles of a triangle is always 180 degrees.

Side and Angle Conditions for a Triangle – Examples

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Side and Angle Conditions for a Triangle – Practice

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Side and Angle Conditions for a Triangle – Summary

Key Learnings from this Text:

  • Triangles are three-sided figures with interior angles that add up to 180 degrees.
  • The triangle inequality theorem is crucial for understanding whether a set of three lengths can form a triangle.
  • Understanding these basic properties helps in solving more complex problems involving triangles and their properties in both academic studies and real-life applications.

Side and Angle Conditions for a Triangle – Frequently Asked Questions

Side and Angle Conditions for a Triangle exercise

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  • Hints

    To form a triangle the sum of the two smaller sides must be greater than the longest side.

    If we have a side of $150$ cm and the sum of the other two sides is less than that, they will not meet. For example, $70 + 30 = 100$.

    As $100 < 150$, these measurements would not form a triangle.

    There are $3$ correct answers here.

    Solution
    • $11$ cm, $4$ cm and $12$ cm will form a triangle as $11 + 4 > 12$
    • $8$ cm, $7$ cm and $13$ cm will form a triangle as $8 + 7 > 13$
    • $6$ cm, $9$ cm and $11$ cm will form a triangle as $6 + 9 > 11$
    ________________________________________________________

    The others will not form a triangle.

    • $5$ cm, $6$ cm and $12$ cm will not form a triangle as $5 + 6 < 12$, they will not meet.
    • $4$ cm, $9$ cm and $13$ cm will not form a triangle as $4 + 9 = 13$, they form a straight line. (See image)
  • Hints

    The third side has to ensure it creates a triangle.

    In this example, one side is $9$ cm and the other side is $5$ cm. In order to form a triangle the third side needs to be $> 4$ as $4 + 5 = 9$ and that would form a line, not a triangle.

    There are $2$ correct answers.

    Solution

    The correct answers are $18$ cm and $20$ cm.

    • $10 + 18 = 28$ and $28 > 25$
    • $10 + 20 = 30$ and $30 > 25$
  • Hints

    The sum of the angles in a triangle is $180^\circ$. Anything more and the angles will not meet.

    For example, $120 + 70 > 180$, therefore will not form a triangle.

    The sides must meet, so the longest side should be shorter than the sum of the other two sides.

    For example, sides of $10$ cm, $6$ cm and $3$ cm will not meet as $6 + 3 < 10$.

    There are $3$ correct answers.

    Solution

    The $3$ correct side and angle conditions are above.

    __________________________________________________

    The $2$ that are not correct are:

    • angles in a triangle have a sum of $180^\circ$ and not $360^\circ$
    • there can be a right angle in a triangle, but not in all triangles.

  • Hints

    Grandpa will need two sides which will make a fairly large triangle. As you can see above, if the two sides are small, Grandpa will not be able to get many flowers in there.

    The sum of the two sides will have to be longer than $28$ ft or they will not form a triangle.

    For example, with sides of $2$ ft, $3$ ft and $7$ ft we cannot form a triangle.

    Solution

    Sides $18$ ft and $21$ ft will add to $28$ ft to give a good-sized triangular flowerbed.

    The others do not work as:

    • they either will not meet - Sides $14$ ft and $12$ ft
    • they form a straight line - Sides $14$ ft and $14$ ft
    • or a very small triangle - Sides $10$ ft and $19$ ft

  • Hints

    The sum of the angles in a triangle is $180^\circ$.

    For example $40 + 35 + 105 = 180^\circ$

    We are looking for all $3$ angles in a triangle to $= 180^\circ$. Therefore, $2$ angles that have a sum greater than $180^\circ$ cannot form a triangle.

    For example, if we have angles of $100^\circ$ and $110^\circ$ then that cannot possibly form a triangle as $100 + 110 > 180$.

    Solution

    The correct answer is angles $132^\circ$ and $55^\circ$.

    This will not work because

    • angles in a triangle $= 180^\circ$
    • here we have $132 + 55 = 187 > 180$
    • the lines will not meet
    • the other pairs of angles are $< 180^\circ$

  • Hints

    The lower limit has to be greater than a value which will create a straight line.

    For example, if one side is $9$ cm and the other side is $8$ cm then we could form a line if we added a side of $1$ cm.

    • $9 - 8 = 1$.
    Therefore, we need the third side to be greater than $1$ cm.

    The upper limit has to be greater than a value which will create a straight line when the two sides are added.

    For example, if one side is $9$ cm and the other side is $8$ cm then we could form a line if we added $9 + 8 = 17$.

    Therefore, we need the third side to be less than $17$ cm in order to form a triangle.

    Solution
    • $a = 3$ cm and $b = 4$ cm has limits $4 - 3 < c < 4 + 3 = 1 < c < 7$
    • $a = 4$ cm and $b = 7$ cm has limits $7 - 4 < c < 7 + 4 = 3 < c < 11$
    • $a = 1$ cm and $b = 6$ cm has limits $6 - 1 < c < 6 + 1 = 5 < c < 7$
    • $a = 2$ cm and $b = 6$ cm has limits $6 - 2 < c < 6 + 2 = 4 < c < 8$
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